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DNA Isolation Lab Report for MBLG1001

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The changes in the protocol were due to the replacement of the 5 mL starting volume

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DNA Isolation Lab Report for MBLG1001
Topics this document covers:
Chemistry Biology Biochemistry Molecular biology GABAA receptor positive allosteric modulators Plasmid preparation Biochemistry methods Ethanol Chloroform Phenol extraction
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Topics this document covers:
Chemistry Biology Biochemistry Molecular biology GABAA receptor positive allosteric modulators Plasmid preparation Biochemistry methods Ethanol Chloroform Phenol extraction
Sample Text:
349 A280 0.613 A260:A280 1.349 : 0.613 = 2.20 RNA contamination Dilution factor used for UV spectrum 20 Diluted [DNA] (ug/ml) (1.349*50) = 67.45 ug/ml DNA Original [DNA] (mg/ml) (67.45*20) = 1349 Yield (mg) 1349*1 = 1349 Yield (mg/g wet weight cells ) 1349 /0.5 = 2.698 Expected yield (mg) based on the theoretical calculations above 3g Calculating DNA content per E coli cell E coli genome as 4.6*10^6 b.p and each b.p is equal to 660MW. Genome DNA in cell is (4.6*10^6*660)/ 6.22*10^23=5.04*10^15=5.04g wet in each cell –A DNA expect to isolate= 1 Ecoli = 3g wet weight cell = 3*10^12 cells Therefore, 1 g wet cell = 1*10^12 cells Today, we stated with 0.5 g wet cells = 0.5*10^12 cells –B In each cell have A g of DNA then B cells will have A* B = 2.5*10^-3g The DNA spectrum ________________ DNA spectrum 1.6 1.4 e c 1.2 n a b 1 r o s b A 0.8...
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